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Grade 8 puzzle 1: Split side lengths around their midpoint

A free grade 8 math puzzle that teaches Split side lengths around their midpoint. Try it first — the hint and the full solution open when you are ready.

Problem 1 · Split side lengths around their midpoint · 3 points

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A rectangle has a perimeter of 56 cm. Its area increases by 20 cm² if its longer side is shortened by 2 cm and its shorter side is lengthened by 2 cm. What was its original area?

Illustration for problem 1
  1. 196
  2. 180
  3. 160
  4. 176
  5. 192
Show a hint
  • The side lengths keep the same sum. Think about how far each one is from their shared midpoint before and after the change.
  • If the original sides are 14 + d and 14 − d, the changed sides are 14 + (d − 2) and 14 − (d − 2). Compare their areas.
Show the answer and solution

Answer: C — 160

The side lengths sum to 28 cm, so their midpoint is 14 cm. Write the original sides as 14 + d and 14 − d. Their area is 196 − d²; after the change it is 196 − (d − 2)². Thus d² − (d − 2)² = 20, giving 4d − 4 = 20 and d = 6. The original sides were 20 cm and 8 cm, so the area was 160 cm². The tempting 180 cm² is the area *after* the change.

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