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Grade 7 puzzle 8: Count unordered groups by dividing out their orders

A free grade 7 math puzzle that teaches Count unordered groups by dividing out their orders. Try it first — the hint and the full solution open when you are ready.

Problem 8 · Count unordered groups by dividing out their orders · 5 points

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Nine dots lie on a circle, and every pair is joined by a straight segment. If no three segments meet at the same point inside the circle, how many distinct crossing points are there?

Illustration for problem 8
  1. 630
  2. 252
  3. 378
  4. 84
  5. 126
Show a hint
  • Focus on one crossing and trace its two segments back to the dots that made it.
  • Any four dots form a quadrilateral. How many pairs of its sides or diagonals cross inside the circle?
Show the answer and solution

Answer: E — 126

Each crossing comes from four dots. For any four dots, exactly one pair of segments crosses inside the circle: the quadrilateral’s two diagonals. Since no three segments meet at one interior point, different groups of four give different crossing points. Counting the dots in order and dividing out their 4 × 3 × 2 × 1 possible orders gives (9 × 8 × 7 × 6) ÷ 24 = 126. The tempting 378 counts all three ways to pair four dots, but only one pairing crosses.

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