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Grade 2 puzzle 12: Extreme cases

A free grade 2 math puzzle that teaches Extreme cases. Try it first — the hint and the full solution open when you are ready.

Problem 12 · Extreme cases · 4 points

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Pip puts 15 pebbles into four pockets. Each pocket has a different number of pebbles, no pocket is empty, and one pocket has exactly 4. What is the most pebbles one pocket can hold?

Illustration for problem 12
  1. 7
  2. 6
  3. 9
  4. 10
  5. 8
Show a hint
  • To make one pocket hold the most, put as few as possible in the others.
Show the answer and solution

Answer: E — 8

One pocket has 4 pebbles. The two smallest other pockets can have 1 and 2, leaving 15 − 4 − 1 − 2 = 8 for the last pocket. The numbers 1, 2, 4, and 8 are all different, so 8 works. A tempting answer is 9, from 1, 2, 3, and 9—but then no pocket has 4.

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